(7k-3)(k^2-2k+7)=0

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Solution for (7k-3)(k^2-2k+7)=0 equation: 


Simplifying
(7k + -3)(k2 + -2k + 7) = 0

Reorder the terms:
(-3 + 7k)(k2 + -2k + 7) = 0

Reorder the terms:
(-3 + 7k)(7 + -2k + k2) = 0

Multiply (-3 + 7k) * (7 + -2k + k2)
(-3(7 + -2k + k2) + 7k * (7 + -2k + k2)) = 0
((7 * -3 + -2k * -3 + k2 * -3) + 7k * (7 + -2k + k2)) = 0
((-21 + 6k + -3k2) + 7k * (7 + -2k + k2)) = 0
(-21 + 6k + -3k2 + (7 * 7k + -2k * 7k + k2 * 7k)) = 0
(-21 + 6k + -3k2 + (49k + -14k2 + 7k3)) = 0

Reorder the terms:
(-21 + 6k + 49k + -3k2 + -14k2 + 7k3) = 0

Combine like terms: 6k + 49k = 55k
(-21 + 55k + -3k2 + -14k2 + 7k3) = 0

Combine like terms: -3k2 + -14k2 = -17k2
(-21 + 55k + -17k2 + 7k3) = 0

Solving
-21 + 55k + -17k2 + 7k3 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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